Difference between revisions of "2021 AMC 10A Problems/Problem 1"
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== Solution 2== | == Solution 2== | ||
+ | We have | ||
<cmath>\begin{align*} | <cmath>\begin{align*} | ||
(2^2-2)-(3^2-3)+(4^2-4) &= 2(2-1)-3(3-1)+4(4-1) \\ | (2^2-2)-(3^2-3)+(4^2-4) &= 2(2-1)-3(3-1)+4(4-1) \\ |
Revision as of 15:20, 24 March 2021
Contents
- 1 Problem
- 2 Solution 1
- 3 Solution 2
- 4 Video Solution (Lightening Fast)
- 5 Video Solution
- 6 Video Solution #0(Very Very Quick Computation)
- 7 Video Solution #1(Quick Computation)
- 8 Video Solution (Arithmetic Computation)
- 9 Video Solution 5
- 10 Video Solution 6
- 11 Video Solution (Problems 1-3)
- 12 See Also
Problem
What is the value of
Solution 1
This corresponds to
-happykeeper
Solution 2
We have
~MRENTHUSIASM
Video Solution (Lightening Fast)
~ Education, the Study of everything
Video Solution
Video Solution #0(Very Very Quick Computation)
https://www.youtube.com/watch?v=m0_UMI2mnZs&list=PLexHyfQ8DMuKqltG3cHT7Di4jhVl6L4YJ&index=2 ~North America Mathematic Contest Go Go Go
Video Solution #1(Quick Computation)
https://youtu.be/C3n2hgBhyXc?t=37 ~ThePuzzlr
Video Solution (Arithmetic Computation)
~ pi_is_3.14
Video Solution 5
~savannahsolver
Video Solution 6
~IceMatrix
Video Solution (Problems 1-3)
~MathWithPi
See Also
2021 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.