Difference between revisions of "2007 AMC 12B Problems/Problem 6"
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Triangle <math>ABC</math> has side lengths <math>AB = 5</math>, <math>BC = 6</math>, and <math>AC = 7</math>. Two bugs start simultaneously from <math>A</math> and crawl along the sides of the triangle in opposite directions at the same speed. They meet at point <math>D</math>. What is <math>BD</math>? | Triangle <math>ABC</math> has side lengths <math>AB = 5</math>, <math>BC = 6</math>, and <math>AC = 7</math>. Two bugs start simultaneously from <math>A</math> and crawl along the sides of the triangle in opposite directions at the same speed. They meet at point <math>D</math>. What is <math>BD</math>? | ||
| − | <math>\mathrm {(A)} 1</math> <math>\mathrm {(B)} 2</math> <math>\mathrm {(C)} 3</math> <math>\mathrm {(D)} 4</math> <math>\mathrm {(E) | + | <math>\mathrm {(A)} 1</math> <math>\mathrm {(B)} 2</math> <math>\mathrm {(C)} 3</math> <math>\mathrm {(D)} 4</math> <math>\mathrm {(E)} 5</math> |
==Solution== | ==Solution== | ||
Revision as of 13:13, 17 October 2007
Problem
Triangle 
has side lengths 
, 
, and 
. Two bugs start simultaneously from 
and crawl along the sides of the triangle in opposite directions at the same speed. They meet at point 
. What is 
?
Solution
An image is supposed to go here. You can help us out by creating one and editing it in. Thanks.
One bug goes to 
. The path that he takes is 
units long. The length of is 
See Also
| 2007 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 5 |
Followed by Problem 7 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
