Difference between revisions of "2013 AMC 8 Problems/Problem 7"
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− | https://www.youtube.com/watch?v=7avOfjhUT6Q | + | https://www.youtube.com/watch?v=7avOfjhUT6Q ~David |
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https://youtu.be/79lJItxCt50 ~savannahsolver | https://youtu.be/79lJItxCt50 ~savannahsolver | ||
Latest revision as of 19:05, 15 April 2023
Problem
Trey and his mom stopped at a railroad crossing to let a train pass. As the train began to pass, Trey counted 6 cars in the first 10 seconds. It took the train 2 minutes and 45 seconds to clear the crossing at a constant speed. Which of the following was the most likely number of cars in the train?
Solution 1
Clearly, for every seconds, cars pass. It's more convenient to have everything in seconds: minutes and seconds seconds. We then set up a ratio:
~megaboy6679 ~MiracleMaths
Solution 2
minutes and seconds is equal to .
Since cars pass at around seconds, there are about groups of cars. There are about , so the closest answer choice is .
Video Solution
https://www.youtube.com/watch?v=7avOfjhUT6Q ~David
https://youtu.be/79lJItxCt50 ~savannahsolver
See Also
2013 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 6 |
Followed by Problem 8 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.