Difference between revisions of "1967 AHSME Problems/Problem 34"
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[[Category: Intermediate Geometry Problems]] | [[Category: Intermediate Geometry Problems]] | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 00:40, 16 August 2023
Problem
Points , , are taken respectively on sides , , and of triangle so that . The ratio of the area of triangle to that of triangle is:
Solution
WLOG, let's assume that is equilateral. Therefore, and . Then . Finding the ratio yields . -Dark_Lord
See also
1967 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 33 |
Followed by Problem 35 | |
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All AHSME Problems and Solutions |
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