Difference between revisions of "2009 AMC 8 Problems/Problem 4"
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==Solution== | ==Solution== | ||
− | The answer is <math>\boxed{\textbf{(B)}}</math> because the longest | + | The answer is <math>\boxed{\textbf{(B)}}</math> because the longest pece cannot fit into the figure. |
Note that the five pieces can be arranged to form the figures in <math>\textbf{(A)},\textbf{(C)},\textbf{(D)},</math> and <math>\textbf{(E)},</math> as shown below: | Note that the five pieces can be arranged to form the figures in <math>\textbf{(A)},\textbf{(C)},\textbf{(D)},</math> and <math>\textbf{(E)},</math> as shown below: |
Revision as of 16:24, 12 November 2023
Contents
[hide]Problem
The five pieces shown below can be arranged to form four of the five figures shown in the choices. Which figure cannot be formed?
Solution
The answer is because the longest pece cannot fit into the figure.
Note that the five pieces can be arranged to form the figures in and as shown below:
~Basketball8 ~MRENTHUSIASM
Video Solution
https://youtu.be/USVVURBLaAc?t=171
See Also
2009 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.