Difference between revisions of "1960 AHSME Problems/Problem 38"
Rockmanex3 (talk | contribs) (Solution to Problem 38) |
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<cmath>a = \frac{b+c}{2}</cmath> | <cmath>a = \frac{b+c}{2}</cmath> | ||
The answer is <math>\boxed{\textbf{(D)}}</math>. | The answer is <math>\boxed{\textbf{(D)}}</math>. | ||
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+ | ==Video Solution== | ||
+ | https://youtu.be/ZdM2ou5Gsuw?t=230 | ||
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+ | ~MathProblemSolvingSkills.com | ||
==See Also== | ==See Also== | ||
− | {{AHSME 40p box|year=1960 | | + | {{AHSME 40p box|year=1960|num-b=37|num-a=39}} |
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+ | [[Category:Introductory Geometry Problems]] |
Latest revision as of 21:27, 28 December 2023
Contents
[hide]Problem
In this diagram and are the equal sides of an isosceles , in which is inscribed equilateral . Designate by , by , and by . Then:
Solution
Since is an equilateral triangle, all of the angles are . The angles in a line add up to , so The angles in a triangle add up to , so Since is isosceles and , by Base-Angle Theorem, The answer is .
Video Solution
https://youtu.be/ZdM2ou5Gsuw?t=230
~MathProblemSolvingSkills.com
See Also
1960 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 37 |
Followed by Problem 39 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 | ||
All AHSME Problems and Solutions |