Difference between revisions of "Rhombus"

Latest revision as of 14:30, 22 February 2024

A rhombus is a geometric figure that lies in a plane. It is defined as a quadrilateral all of whose sides are congruent. It is a special type of parallelogram, and its properties (aside from those properties of parallelograms) include:

Its diagonals divide the figure into 4 congruent triangles.
Its diagonals are perpendicular bisectors of eachother.
If all of a rhombus' angles are right angles, then the rhombus is a square.

Proofs

Proof that a rhombus is a parallelogram

All sides of a rhombus are congruent, so opposite sides are congruent, which is one of the properties of a parallelogram.

Or, there is always the longer way:

In rhombus $ABCD$ , all 4 sides are congruent (definition of a rhombus).

$AB\cong CD$ , $BC\cong DA$ , and $AC\cong AC$ .

By the SSS Postulate, $\triangle ABC\cong\triangle CDA$ .

Corresponding parts of congruent triangles are congruent, so $\angle BAC\cong BCA$ and $\angle B\cong\angle D$ . The same can be done for the two other angles, so $\angle A\cong\angle C$ .

Convert the congruences into measures to get $m\angle A=m\angle C$ and $m\angle B=m\angle D$ . Adding these two equations yields $m\angle A+m\angle B=m\angle C+m\angle D$ .

The interior angles of a quadrilateral add up to 360 degrees, so $m\angle A+m\angle B+m\angle C+m\angle D=360$ , or $m\angle A+m\angle B=360-m\angle C-m\angle D$ .

Substituting gives $m\angle C+m\angle D=360-m\angle C-m\angle D$ . When simplified, $m\angle C+m\angle D=180$ .

If two lines are cut by a transversal and same-side interior angles add up to 180 degrees, the lines are parallel. This means $AD\|BC$ . The same can be done for the other two sides, and know we know that opposite sides are parallel. Therefore, a rhombus is a parallelogram.

Proof that the diagonals of a rhombus divide it into 4 congruent triangles

In rhombus $ABCD$ , $M$ is the point at which the diagonals intersect.

Since the diagonals of a rhombus are bisectors of eachother, $AM\cong MC$ and $BM\cong MD$ .

Also, all sides are congruent.

By the SSS Postulate, the 4 triangles formed by the diagonals of a rhombus are congruent.

Proof that the diagonals of a rhombus are perpendicular

Continuation of above proof:

Corresponding parts of congruent triangles are congruent, so all 4 angles (the ones in the middle) are congruent.

This leads to the fact that they are all equal to 90 degrees, and the diagonals are perpendicular to each other.

Example Problems

Introductory

@@ Line 1: / Line 1: @@
 A '''rhombus''' is a geometric figure that lies in a [[plane]].  It is defined as a [[quadrilateral]] all of whose sides are [[congruent (geometry) | congruent]].  It is a special type of [[parallelogram]], and its properties (aside from those properties of parallelograms) include:
 * Its diagonals divide the figure into 4 congruent [[triangle]]s.
-* Its diagonals are [[perpendicular]].
+* Its diagonals are [[perpendicular]] [[bisect]]ors of eachother.
 * If all of a rhombus' [[angle]]s are [[right angle]]s, then the rhombus is a [[square (geometry) | square]].
@@ Line 7: / Line 7: @@
 ==Proofs==
-This article would be greatly enhanced by the proofs of the above facts.
+===Proof that a rhombus is a parallelogram===
+All sides of a rhombus are congruent, so opposite sides are congruent, which is one of the properties of a parallelogram.
+Or, there is always the longer way:
+In rhombus <math>ABCD</math>, all 4 sides are congruent (definition of a rhombus).
+<math>AB\cong CD</math>, <math>BC\cong DA</math>, and <math>AC\cong AC</math>.
+By the SSS Postulate, <math>\triangle ABC\cong\triangle CDA</math>.
+Corresponding parts of congruent triangles are congruent, so <math>\angle BAC\cong BCA</math> and <math>\angle B\cong\angle D</math>. The same can be done for the two other angles, so <math>\angle A\cong\angle C</math>.
+Convert the congruences into measures to get <math>m\angle A=m\angle C</math> and <math>m\angle B=m\angle D</math>. Adding these two equations yields <math>m\angle A+m\angle B=m\angle C+m\angle D</math>.
+The interior angles of a quadrilateral add up to 360 degrees, so <math>m\angle A+m\angle B+m\angle C+m\angle D=360</math>, or <math>m\angle A+m\angle B=360-m\angle C-m\angle D</math>.
+Substituting gives <math>m\angle C+m\angle D=360-m\angle C-m\angle D</math>. When simplified, <math>m\angle C+m\angle D=180</math>.
-===Proof that a rhombus is a parallelogram===
+If two lines are cut by a transversal and same-side interior angles add up to 180 degrees, the lines are parallel. This means <math>AD\|BC</math>. The same can be done for the other two sides, and know we know that opposite sides are parallel. Therefore, a rhombus is a parallelogram.
 ===Proof that the diagonals of a rhombus divide it into 4 congruent triangles===
+In rhombus <math>ABCD</math>, <math>M</math> is the point at which the diagonals intersect.
+Since the diagonals of a rhombus are bisectors of eachother, <math>AM\cong MC</math> and <math>BM\cong MD</math>.
+Also, all sides are congruent.
+By the SSS Postulate, the 4 triangles formed by the diagonals of a rhombus are congruent.
 ===Proof that the diagonals of a rhombus are perpendicular===
+Continuation of above proof:
+Corresponding parts of congruent triangles are congruent, so all 4 angles (the ones in the middle) are congruent.
+This leads to the fact that they are all equal to 90 degrees, and the diagonals are perpendicular to each other.
 == Example Problems ==
 === Introductory ===
+* [[2022_AMC_12B Problems/Problem_2 | 2022 AMC 10B Problem 2]]
 * [[2006_AMC_10B_Problems/Problem_15 | 2006 AMC 10B Problem 15]]
-{{stub}}
+[[Category:Geometry]]

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