Difference between revisions of "2016 AMC 8 Problems/Problem 7"
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Our answer must have an odd exponent in order for it to not be a square. Because <math>4</math> is a perfect square, <math>4^{2019}</math> is also a perfect square, so our answer is <math>\boxed{\textbf{(B) }2^{2017}}</math>. | Our answer must have an odd exponent in order for it to not be a square. Because <math>4</math> is a perfect square, <math>4^{2019}</math> is also a perfect square, so our answer is <math>\boxed{\textbf{(B) }2^{2017}}</math>. | ||
− | ==Solution | + | ==Video Solution== |
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− | - | + | https://youtu.be/ymZQgW-cL4s?si=NbFD5ZIPgtojqEaj |
− | + | A solution so simple a 12-year-old made it! | |
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+ | ~Elijahman~ | ||
==Video Solution (CREATIVE THINKING!!!)== | ==Video Solution (CREATIVE THINKING!!!)== | ||
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~Education, the Study of Everything | ~Education, the Study of Everything | ||
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==Video Solution== | ==Video Solution== |
Latest revision as of 10:47, 20 June 2024
Contents
[hide]Problem
Which of the following numbers is not a perfect square?
Solution 1
Our answer must have an odd exponent in order for it to not be a square. Because is a perfect square, is also a perfect square, so our answer is .
Video Solution
https://youtu.be/ymZQgW-cL4s?si=NbFD5ZIPgtojqEaj
A solution so simple a 12-year-old made it!
~Elijahman~
Video Solution (CREATIVE THINKING!!!)
~Education, the Study of Everything
Video Solution
https://www.youtube.com/watch?v=BZKzpY_pH5A ~David
~savannahsolver
See Also
2016 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 6 |
Followed by Problem 8 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.