Difference between revisions of "2003 AMC 10B Problems/Problem 1"

(AMC 10 B 2003- Problem 1)
 
m
Line 1: Line 1:
1.  Which of the following is the same as
+
==Problem==
  
<math>\frac{2-4+6-8+10-12+14}{3-6+9-12+15-18+21}</math>?
+
Which of the following is the same as <math>\dfrac{2-4+6-8+10-12+14}{3-6+9-12+15-18+21}</math>?
  
 
<math>\textbf{(A)}\ -1 \qquad
 
<math>\textbf{(A)}\ -1 \qquad
Line 8: Line 8:
 
\textbf{(D)}\ 1 \qquad
 
\textbf{(D)}\ 1 \qquad
 
\textbf{(E)}\ \frac{14}{3}</math>
 
\textbf{(E)}\ \frac{14}{3}</math>
 +
 +
==Solution==
 +
 +
{{solution}}
 +
 +
==See Also==
 +
 +
{{AMC10 box|year=2003|ab=B|before=First Question|num-a=2}}
 +
[[Category: Introductory Algebra Problems]]

Revision as of 15:39, 2 March 2011

Problem

Which of the following is the same as $\dfrac{2-4+6-8+10-12+14}{3-6+9-12+15-18+21}$?

$\textbf{(A)}\ -1 \qquad \textbf{(B)}\ -\frac23 \qquad \textbf{(C)}\ \frac23 \qquad \textbf{(D)}\ 1 \qquad \textbf{(E)}\ \frac{14}{3}$

Solution

This problem needs a solution. If you have a solution for it, please help us out by adding it.

See Also

2003 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
First Question
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions