Difference between revisions of "2003 AMC 10B Problems/Problem 1"
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| + | We can rewrite the given fraction as: | ||
| + | \[\frac{-3(2)+2(7)}{3(-3)+3(7)}=\frac{2(4)}{3(4)}=\frac{2}{3} \longrightarrow \boxed{\textbf{(C)}}$ | ||
==See Also== | ==See Also== | ||
{{AMC10 box|year=2003|ab=B|before=First Question|num-a=2}} | {{AMC10 box|year=2003|ab=B|before=First Question|num-a=2}} | ||
[[Category: Introductory Algebra Problems]] | [[Category: Introductory Algebra Problems]] | ||
Revision as of 15:24, 31 May 2011
Problem
Which of the following is the same as 
?
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it. We can rewrite the given fraction as:
\[\frac{-3(2)+2(7)}{3(-3)+3(7)}=\frac{2(4)}{3(4)}=\frac{2}{3} \longrightarrow \boxed{\textbf{(C)}}$
See Also
| 2003 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
