Difference between revisions of "1997 PMWC Problems/Problem I5"

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<math>(A+C)-(B+C)=A-B=\boxed{20}</math>
 
<math>(A+C)-(B+C)=A-B=\boxed{20}</math>
  
==See also==
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==See Also==
 
{{PMWC box|year=1997|num-b=I3|num-a=I5}}
 
{{PMWC box|year=1997|num-b=I3|num-a=I5}}

Revision as of 15:03, 15 May 2012

Problem

Two squares of different sizes overlap as shown in the given figure. What is the difference between the non-overlapping areas?

1997 PMWC individual 5.png

Solution

Let the area of the non-shaded region of the 6 by 6 square by A. Let the area of the non-shaded region of the 4 by 4 square by B. Let the shaded area be C.

$A+C=36$

$B+C=16$

$(A+C)-(B+C)=A-B=\boxed{20}$

See Also

1997 PMWC (Problems)
Preceded by
Problem I3
Followed by
Problem I5
I: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
T: 1 2 3 4 5 6 7 8 9 10