Difference between revisions of "2006 AMC 8 Problems/Problem 3"
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== Solution == | == Solution == | ||
When Elisa started, she finished a lap in <math> \frac{25}{10}=2.5 </math> minutes. Now, she finishes a lap is <math> \frac{24}{12}= 2 </math> minutes. The difference is <math> 2.5-2=\boxed{\textbf{(A)}\ \frac{1}{2}} </math>. | When Elisa started, she finished a lap in <math> \frac{25}{10}=2.5 </math> minutes. Now, she finishes a lap is <math> \frac{24}{12}= 2 </math> minutes. The difference is <math> 2.5-2=\boxed{\textbf{(A)}\ \frac{1}{2}} </math>. | ||
| − | + | ==See Also== | |
{{AMC8 box|year=2006|num-b=2|num-a=4}} | {{AMC8 box|year=2006|num-b=2|num-a=4}} | ||
Revision as of 23:51, 12 November 2012
Problem
Elisa swims laps in the pool. When she first started, she completed 10 laps in 25 minutes. Now, she can finish 12 laps in 24 minutes. By how many minutes has she improved her lap time?
Solution
When Elisa started, she finished a lap in 
minutes. Now, she finishes a lap is 
minutes. The difference is 
.
See Also
| 2006 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
