Difference between revisions of "1997 AHSME Problems/Problem 5"
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+ | ==Problem== | ||
+ | |||
+ | A rectangle with perimeter <math>176</math> is divided into five congruent rectangles as shown in the diagram. What is the perimeter of one of the five congruent rectangles? | ||
+ | <asy> | ||
+ | defaultpen(linewidth(.8pt)); | ||
+ | draw(origin--(0,3)--(4,3)--(4,0)--cycle); | ||
+ | draw((0,1)--(4,1)); | ||
+ | draw((2,0)--midpoint((0,1)--(4,1))); | ||
+ | real r = 4/3; | ||
+ | draw((r,3)--foot((r,3),(0,1),(4,1))); | ||
+ | draw((2r,3)--foot((2r,3),(0,1),(4,1)));</asy> | ||
+ | |||
+ | <math> \mathrm{(A)\ } 35.2 \qquad \mathrm{(B) \ }76 \qquad \mathrm{(C) \ } 80 \qquad \mathrm{(D) \ } 84 \qquad \mathrm{(E) \ }86 </math> | ||
+ | |||
+ | ==Solution== | ||
+ | |||
+ | Let <math>l</math> represent the length of one of the smaller rectangles, and let <math>w</math> represent the width of one of the smaller rectangles, with <math>w < l</math>. | ||
+ | |||
+ | From the large rectangle, we see that the top has length <math>3w</math>, the right has length <math>l + w</math>, the bottom has length <math>2l</math>, and the left has length <math>l + 2</math>. | ||
+ | |||
+ | Since the perimeter of the large rectangle is <math>176</math>, we know that <math>172 = 3w + l + w + 2l + l + w</math>, or <math>172 = 5w + 4l</math> | ||
+ | |||
+ | From the top and bottom of the large rectangle, we know that <math>3w = 2l</math>, or <math>l = 1.5w</math>. | ||
+ | |||
+ | Plugging that into the first equation, we get <math>176 = 5w + 4(1.5)w</math> | ||
+ | |||
+ | <math>176 = 11w</math> | ||
+ | |||
+ | <math>w = 16</math> | ||
+ | |||
+ | <math>l = 1.5w = 24</math> | ||
+ | |||
+ | <math>P = 2l + 2w = 2(16 + 24) = 80</math>, and the answer is <math>\boxed{C}</math> | ||
+ | |||
== See also == | == See also == | ||
{{AHSME box|year=1997|num-b=4|num-a=6}} | {{AHSME box|year=1997|num-b=4|num-a=6}} | ||
+ | {{MAA Notice}} |
Latest revision as of 13:12, 5 July 2013
Problem
A rectangle with perimeter is divided into five congruent rectangles as shown in the diagram. What is the perimeter of one of the five congruent rectangles?
Solution
Let represent the length of one of the smaller rectangles, and let represent the width of one of the smaller rectangles, with .
From the large rectangle, we see that the top has length , the right has length , the bottom has length , and the left has length .
Since the perimeter of the large rectangle is , we know that , or
From the top and bottom of the large rectangle, we know that , or .
Plugging that into the first equation, we get
, and the answer is
See also
1997 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 4 |
Followed by Problem 6 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.