Difference between revisions of "2005 PMWC Problems/Problem I4"
(Created page with "==Problem== The larger circle has radius 12 cm. Each of the six identical smaller circles touches its two neighbours and the larger circle. What is the radius of the smaller circ...") |
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} | } | ||
</asy> | </asy> | ||
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+ | ==Solution== | ||
+ | <asy> | ||
+ | unitsize(0.5cm); | ||
+ | draw((0,3)..(3,0)..(0,-3)..(-3,0)..cycle); | ||
+ | for (int i=0;i<6;i=i+1){ | ||
+ | draw(dir(60*i)..3*dir(60*i)..cycle); | ||
+ | } | ||
+ | draw((0,1)..(0,-1)..cycle,rgb(1,0,0)); | ||
+ | </asy> | ||
+ | Adding a circle in the middle makes the solution obvious. Since the radius of the big circle is <math>12</math> cm, then the diameter of the big circle is <math>24</math> cm. But this is also <math>3</math> of the little circle's diameter! Therefore, the diameter of the little circle is <math>24\div3=8</math> cm and the radius is therefore <math>\boxed{4 \text{cm}}</math>. | ||
+ | |||
+ | == See also == | ||
+ | {{PMWC box|year=2005|num-b=I3|num-a=I5}} | ||
+ | |||
+ | [[Category:Introductory Algebra Problems]] |
Latest revision as of 18:15, 6 October 2013
Problem
The larger circle has radius 12 cm. Each of the six identical smaller circles touches its two neighbours and the larger circle. What is the radius of the smaller circle?
Solution
Adding a circle in the middle makes the solution obvious. Since the radius of the big circle is cm, then the diameter of the big circle is cm. But this is also of the little circle's diameter! Therefore, the diameter of the little circle is cm and the radius is therefore .
See also
2005 PMWC (Problems) | ||
Preceded by Problem I3 |
Followed by Problem I5 | |
I: 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 T: 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 |