Difference between revisions of "2013 AMC 8 Problems/Problem 10"

Revision as of 16:39, 27 November 2013

What is the ratio of the least common multiple of 180 and 594 to the greatest common factor of 180 and 594?

$\textbf{(A)}\ 110 \qquad \textbf{(B)}\ 165 \qquad \textbf{(C)}\ 330 \qquad \textbf{(D)}\ 625 \qquad \textbf{(E)}\ 660$

This is very easy. To find the LCM of 180 and 594, find the prime factorization of both.

The prime factorization of 180 = $3^2 \times 5 \times 2^2$

2013 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 9	Followed by Problem 11
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

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 ==Solution==
+This is very easy. To find the LCM of 180 and 594, find the prime factorization of both.
+The prime factorization of 180 = <math>3^2 \times  5 \times 2^2</math>
 ==See Also==
 {{AMC8 box|year=2013|num-b=9|num-a=11}}
 {{MAA Notice}}