Difference between revisions of "1971 Canadian MO Problems/Problem 3"
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Revision as of 16:17, 7 August 2016
Problem
is a quadrilateral with . If is greater than , prove that .
Solution
Consider triangles and . These triangles share two of the same side lengths. Thus, by the Hinge Theorem, since we are given that , we have .
See Also
1971 Canadian MO (Problems) | ||
Preceded by Problem 2 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • | Followed by Problem 4 |