Difference between revisions of "2016 AMC 8 Problems/Problem 4"
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==Solution== | ==Solution== | ||
| − | When Cheenu was a boy, he could run <math>15</math> miles in <math>210</math> minutes, thus running <math>14</math> minutes per mile. When he is an old man, he can walk <math>10</math> miles in <math>240</math> minutes, thus walking <math>24</math> minutes per mile. Therefore it takes him <math>\textbf{(B) }10< | + | When Cheenu was a boy, he could run <math>15</math> miles in <math>210</math> minutes, thus running <math>14</math> minutes per mile. When he is an old man, he can walk <math>10</math> miles in <math>240</math> minutes, thus walking <math>24</math> minutes per mile. Therefore it takes him <math>boxed</math>\textbf{(B) }10<math> minutes longer to walk a mile now compared to when he was a boy.</math> |
{{AMC8 box|year=2016|num-b=3|num-a=5}} | {{AMC8 box|year=2016|num-b=3|num-a=5}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 10:22, 23 November 2016
When Cheenu was a boy he could run 
miles in 
hours and 
minutes. As an old man he can now walk 
miles in 
hours. How many minutes longer does it take for him to walk a mile now compared to when he was a boy?
Solution
When Cheenu was a boy, he could run miles in 
minutes, thus running 
minutes per mile. When he is an old man, he can walk miles in 
minutes, thus walking 
minutes per mile. Therefore it takes him 
\textbf{(B) }10
| 2016 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
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| All AJHSME/AMC 8 Problems and Solutions | ||
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