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Difference between revisions of "Mock USAMO by probability1.01 dropped problems"

 
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at <math>N</math>, prove that <math>MN, EF, and BC</math> concur.
 
at <math>N</math>, prove that <math>MN, EF, and BC</math> concur.
 
''Reason: The whole incircle business seemed rather artificial. Besides, it wasn’t that difficult.''
 
''Reason: The whole incircle business seemed rather artificial. Besides, it wasn’t that difficult.''
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[[Image:Mock_usamo.png]]
 
[[Mock USAMO by probability1.01 dropped problems/Problem 2|Solution]]
 
[[Mock USAMO by probability1.01 dropped problems/Problem 2|Solution]]
  

Revision as of 15:45, 2 September 2006

Problem 1

Solution

Problem 2

In triangle $ABC$, $AB \not= AC$, let the incircle touch $BC$, $CA$, and $AB$ at $D$, $E$, and $F$ respectively. Let $P$ be a point on $AD$ on the opposite side of $EF$ from $D$. If $EP$ and $AB$ meet at $M$, and $FP$ and $AC$ meet at $N$, prove that $MN, EF, and BC$ concur. Reason: The whole incircle business seemed rather artificial. Besides, it wasn’t that difficult. Mock usamo.png Solution

Problem 3

Solution

Problem 4

Solution

Problem 5

Solution

Problem 6

Solution

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