Difference between revisions of "Mock USAMO by probability1.01 dropped problems"

(Problem 2)
(Problem 2)
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at <math>D</math>, <math>E</math>, and <math>F</math> respectively. Let <math>P</math> be a point on <math>AD</math> on the opposite
 
at <math>D</math>, <math>E</math>, and <math>F</math> respectively. Let <math>P</math> be a point on <math>AD</math> on the opposite
 
side of <math>EF</math> from <math>D</math>. If <math>EP</math> and <math>AB</math> meet at <math>M</math>, and <math>FP</math> and <math>AC</math> meet
 
side of <math>EF</math> from <math>D</math>. If <math>EP</math> and <math>AB</math> meet at <math>M</math>, and <math>FP</math> and <math>AC</math> meet
at <math>N</math>, prove that <math>MN, EF, and BC</math> concur.
+
at <math>N</math>, prove that <math>MN</math>, <math>EF</math>, and <math>BC</math> concur.
 
''Reason: The whole incircle business seemed rather artificial. Besides, it wasn’t that difficult.''
 
''Reason: The whole incircle business seemed rather artificial. Besides, it wasn’t that difficult.''
  

Revision as of 15:46, 2 September 2006

Problem 1

Solution

Problem 2

In triangle $ABC$, $AB \not= AC$, let the incircle touch $BC$, $CA$, and $AB$ at $D$, $E$, and $F$ respectively. Let $P$ be a point on $AD$ on the opposite side of $EF$ from $D$. If $EP$ and $AB$ meet at $M$, and $FP$ and $AC$ meet at $N$, prove that $MN$, $EF$, and $BC$ concur. Reason: The whole incircle business seemed rather artificial. Besides, it wasn’t that difficult.

Mock usamo.png

Solution

Problem 3

Solution

Problem 4

Solution

Problem 5

Solution

Problem 6

Solution