Difference between revisions of "1960 AHSME Problems/Problem 10"

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==Solution==
 
==Solution==
<math>\fbox{(D)4}</math>
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<math>\fbox{(C)3}</math>
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Because No men are good negates All men are good.
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==See Also==
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{{AHSME 40p box|year=1960|num-b=9|num-a=11}}
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[[Category:Introductory Logic Problems]]

Latest revision as of 08:03, 18 July 2024

Problem 10

Given the following six statements: \[\text{(1) All women are good drivers}\] \[\text{(2) Some women are good drivers}\] \[\text{(3) No men are good drivers}\] \[\text{(4) All men are bad drivers}\] \[\text{(5) At least one man is a bad driver}\] \[\text{(6) All men are good drivers.}\]


The statement that negates statement $(6)$ is:


$\textbf{(A) }(1)\qquad \textbf{(B) }(2)\qquad \textbf{(C) }(3)\qquad \textbf{(D) }(4)\qquad \textbf{(E) }(5)$


Solution

$\fbox{(C)3}$ Because No men are good negates All men are good.


See Also

1960 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40
All AHSME Problems and Solutions