Difference between revisions of "2019 AMC 10A Problems/Problem 1"
(Created page with "The first part can be rewritten as <cmath>2^{0^{1}}=2^{0}=1</cmath>. The second part is <cmath>(1^{1})^{9}=1^{9}=1</cmath>. Adding these up gives \fbox{(C) <cmath>2</cmath>}") |
(→Video Solution by T2L Academy) |
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− | + | == Problem == | |
− | + | What is the value of <cmath>2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9?</cmath> | |
+ | |||
+ | <math>\textbf{(A) } 0 \qquad\textbf{(B) } 1 \qquad\textbf{(C) } 2 \qquad\textbf{(D) } 3 \qquad\textbf{(E) } 4</math> | ||
+ | |||
+ | == Solution == | ||
+ | <math>2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9= 1+1 = \boxed{\textbf{(C) } 2}</math>. | ||
+ | |||
+ | ==Video Solution by Education, the Study of Everything== | ||
+ | https://youtu.be/K8je0WYBHFc | ||
+ | |||
+ | ~Education, The Study Of Everything | ||
+ | |||
+ | == Video Solution by WhyMath== | ||
+ | https://youtu.be/Ad8WKcwZcTA | ||
+ | |||
+ | ~savannahsolver | ||
+ | |||
+ | == Video Solution by T2L Academy== | ||
+ | https://youtu.be/OhCy9c2RTFo?si=UPgBHbW5Bn0yxP1s | ||
+ | |||
+ | == See Also == | ||
+ | {{AMC10 box|year=2019|ab=A|before=First Problem|num-a=2}} | ||
+ | {{MAA Notice}} |
Latest revision as of 11:55, 16 July 2024
Contents
Problem
What is the value of
Solution
.
Video Solution by Education, the Study of Everything
~Education, The Study Of Everything
Video Solution by WhyMath
~savannahsolver
Video Solution by T2L Academy
https://youtu.be/OhCy9c2RTFo?si=UPgBHbW5Bn0yxP1s
See Also
2019 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.