Difference between revisions of "2019 AMC 12A Problems/Problem 1"
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+ | ==Problem== | ||
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The area of a pizza with radius <math>4</math> is <math>N</math> percent larger than the area of a pizza with radius <math>3</math> inches. What is the integer closest to <math>N</math>? | The area of a pizza with radius <math>4</math> is <math>N</math> percent larger than the area of a pizza with radius <math>3</math> inches. What is the integer closest to <math>N</math>? | ||
<math>\textbf{(A) } 25 \qquad\textbf{(B) } 33 \qquad\textbf{(C) } 44\qquad\textbf{(D) } 66 \qquad\textbf{(E) } 78</math> | <math>\textbf{(A) } 25 \qquad\textbf{(B) } 33 \qquad\textbf{(C) } 44\qquad\textbf{(D) } 66 \qquad\textbf{(E) } 78</math> | ||
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+ | ==Solution== | ||
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+ | The area of the larger pizza is <math>16\pi</math>, while the area of the smaller pizza is <math>9\pi</math>. Therefore, the larger pizza is <math>\frac{7\pi}{9\pi} \cdot 100\%</math> bigger than the smaller pizza. <math>\frac{7\pi}{9\pi} \cdot 100\% = 77.777....</math>, which is closest to <math>\boxed{\textbf{(E) }78}</math>. | ||
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+ | ==Video Solution 1== | ||
+ | https://youtu.be/SbUEin-OE-k | ||
+ | |||
+ | ~Education, the Study of Everything | ||
+ | |||
+ | ==See Also== | ||
+ | |||
+ | {{AMC12 box|year=2019|ab=A|before=First Problem|num-a=2}} | ||
+ | {{MAA Notice}} |
Latest revision as of 17:31, 30 October 2022
Contents
Problem
The area of a pizza with radius is percent larger than the area of a pizza with radius inches. What is the integer closest to ?
Solution
The area of the larger pizza is , while the area of the smaller pizza is . Therefore, the larger pizza is bigger than the smaller pizza. , which is closest to .
Video Solution 1
~Education, the Study of Everything
See Also
2019 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by First Problem |
Followed by Problem 2 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
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