Difference between revisions of "2019 AMC 12B Problems/Problem 4"

Latest revision as of 14:28, 14 February 2019

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-==Problem==
+#REDIRECT[[2019_AMC_10B_Problems/Problem_6]]
-A positive integer <math>n</math> satisfies the equation <math>(n+1)!+(n+2)!=440\cdot n!</math>. What is the sum of the digits of <math>n</math>?
-<math>\textbf{(A) } 2 \qquad \textbf{(B) } 5 \qquad \textbf{(C) } 10\qquad \textbf{(D) } 12 \qquad \textbf{(E) } 15</math>
-==Solution==
-==See Also==
-{{AMC12 box|year=2019|ab=B|num-b=3|num-a=5}}
-{{MAA Notice}}