Difference between revisions of "2019 AMC 10A Problems/Problem 1"

Latest revision as of 12:55, 16 July 2024

What is the value of $2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9?$

$\textbf{(A) } 0 \qquad\textbf{(B) } 1 \qquad\textbf{(C) } 2 \qquad\textbf{(D) } 3 \qquad\textbf{(E) } 4$

$2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9= 1+1 = \boxed{\textbf{(C) } 2}$ .

~Education, The Study Of Everything

~savannahsolver

2019 AMC 10A (Problems • Answer Key • Resources)
Preceded by First Problem	Followed by Problem 2
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AMC 10 Problems and Solutions

@@ Line 1: / Line 1: @@
-==Problem 1==
+== Problem ==
 What is the value of <cmath>2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9?</cmath>
 <math>\textbf{(A) } 0 \qquad\textbf{(B) } 1 \qquad\textbf{(C) } 2 \qquad\textbf{(D) } 3 \qquad\textbf{(E) } 4</math>
-======Solution======
+== Solution ==
-The first part can be rewritten as <cmath>2^{0^{1}}=2^{0}=1.</cmath>
+<math>2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9=  1+1 = \boxed{\textbf{(C) } 2}</math>.
-The second part is <cmath>(1^{1})^{9}=1^{9}=1.</cmath>
-Adding these up gives <math>\boxed{\textbf{(C) }2}.</math>
+==Video Solution by Education, the Study of Everything==
+https://youtu.be/K8je0WYBHFc
+~Education, The Study Of Everything
+== Video Solution by WhyMath==
+https://youtu.be/Ad8WKcwZcTA
+~savannahsolver
+== Video Solution by T2L Academy==
+https://youtu.be/OhCy9c2RTFo?si=UPgBHbW5Bn0yxP1s
 == See Also ==
 {{AMC10 box|year=2019|ab=A|before=First Problem|num-a=2}}
 {{MAA Notice}}