Difference between revisions of "1956 AHSME Problems/Problem 8"
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+ | == Problem 8== | ||
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+ | If <math>8\cdot2^x = 5^{y + 8}</math>, then when <math>y = - 8,x = </math> | ||
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+ | <math>\textbf{(A)}\ - 4 \qquad\textbf{(B)}\ - 3 \qquad\textbf{(C)}\ 0 \qquad\textbf{(D)}\ 4 \qquad\textbf{(E)}\ 8 </math> | ||
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== Solution == | == Solution == | ||
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This simply gives that <math>x=-3</math>. | This simply gives that <math>x=-3</math>. | ||
Therefore, the answer is <math>\fbox{(B) -3}</math>. | Therefore, the answer is <math>\fbox{(B) -3}</math>. | ||
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+ | ==See Also== | ||
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+ | {{AHSME box|year=1956|num-b=7|num-a=9}} | ||
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+ | [[Category:Introductory Algebra Problems]] | ||
+ | {{MAA Notice}} |
Latest revision as of 21:25, 2 June 2022
Problem 8
If , then when
Solution
Simple substitution yields Reducing the equation gives Dividing by 8 gives This simply gives that . Therefore, the answer is .
See Also
1956 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 7 |
Followed by Problem 9 | |
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All AHSME Problems and Solutions |
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