Difference between revisions of "2002 AIME II Problems/Problem 1"
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How many distinct values of <math>z</math> are possible? | How many distinct values of <math>z</math> are possible? | ||
Latest revision as of 20:56, 11 February 2020
Problem
Given that
How many distinct values of are possible?
Solution
We express the numbers as and . From this, we have Because and are digits, and and are both between 1 and 9 (from condition 1), there are possible values (since all digits except can be expressed this way).
See also
2002 AIME II (Problems • Answer Key • Resources) | ||
Preceded by First Question |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.