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Difference between revisions of "1968 IMO Problems"
 
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* [[1968 IMO]] * [http://www.artofproblemsolving.com/Forum/resources.php?c=1&cid=16&year=1968 IMO 1968 Problems on the Resources page] * [[IMO Problems and Solutions, with authors]] * [[Mathematics competition resources]] {{IMO box|year=1968|before=[[1967 IMO]]|after=[[1969 IMO]]}}
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* [[1968 IMO]]  
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* [http://www.artofproblemsolving.com/Forum/resources.php?c=1&cid=16&year=1968 IMO 1968 Problems on the Resources page]  
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* [[IMO Problems and Solutions, with authors]]  
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* [[Mathematics competition resources]]  
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{{IMO box|year=1968|before=[[1967 IMO]]|after=[[1969 IMO]]}}

Latest revision as of 12:24, 29 January 2021

Problems of the 10th IMO 1968 in USSR.

Problem 1

Prove that there is one and only one triangle whose side lengths are consecutive integers, and one of whose angles is twice as large as another.

Solution

Problem 2

Find all natural numbers $x$ such that the product of their digits (in decimal notation) is equal to $x^2 - 10x - 22$.

Solution

Problem 3

Consider the system of equations \[ax_1^2 + bx_1 + c = x_2\] \[ax_2^2 + bx_2 + c = x_3\] \[\cdots\] \[ax_{n-1}^2 + bx_{n-1} + c = x_n\] \[ax_n^2 + bx_n + c = x_1\] with unknowns $x_1, x_2, \cdots, x_n$ where $a, b, c$ are real and $a \neq 0$. Let $\Delta = (b - 1)^2 - 4ac$. Prove that for this system

(a) if $\Delta < 0$, there is no solution,

(b) if $\Delta = 0$, there is exactly one solution,

(c) if $\Delta > 0$, there is more than one solution.

Solution

Problem 4

Prove that in every tetrahedron there is a vertex such that the three edges meeting there have lengths which are the sides of a triangle.

Solution

Problem 5

Let $f$ be a real-valued function defined for all real numbers $x$ such that, for some positive constant $a$, the equation \[f(x + a) = \frac{1}{2} + \sqrt{f(x) - (f(x))^2}\] holds for all $x$.

(a) Prove that the function $f$ is periodic (i.e., there exists a positive number $b$ such that $f(x + b) = f(x)$ for all $x$).

(b) For $a = 1$, give an example of a non-constant function with the required properties.

Solution

Problem 6

For every natural number $n$, evaluate the sum \[\sum_{k = 0}^\infty\bigg[\frac{n + 2^k}{2^{k + 1}}\bigg] = \Big[\frac{n + 1}{2}\Big] + \Big[\frac{n + 2}{4}\Big] + \cdots + \bigg[\frac{n + 2^k}{2^{k + 1}}\bigg] + \cdots\] (The symbol $[x]$ denotes the greatest integer not exceeding $x$.)

Solution

1968 IMO (Problems) • Resources
Preceded by
1967 IMO 		1 • 2 • 3 • 4 • 5 • 6 Followed by
1969 IMO
All IMO Problems and Solutions
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