Difference between revisions of "2023 AMC 10A Problems/Problem 3"

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#redirect[[2023 AMC 12A Problems/Problem 3]]
==Problem==
 
How many positive perfect squares less than <math>2023</math> are divisible by <math>5</math>?
 
 
 
<cmath>\textbf{(A) } 8 \qquad\textbf{(B) }9 \qquad\textbf{(C) }10 \qquad\textbf{(D) }11 \qquad\textbf{(E) } 12</cmath>
 
 
 
==Solution 1==
 
Note that <math>45^{2}=2025</math> so the list is <math>5,10,15,20,25,30,35,40</math> there are <math>8</math> elements so the answer is <math>\text{\boxed{(A)}}</math>
 
 
 
==See Also==
 
{{AMC10 box|year=2023|ab=A|before=2|num-a=4}}
 

Latest revision as of 22:08, 9 November 2023