Difference between revisions of "2020 AMC 10B Problems/Problem 1"
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Thus, the sum of the three groups is <math>2 \cdot 1 + 1 + 1 + 1 = 5</math> or <math>\boxed{\textbf{(D)}\ 5}</math> | Thus, the sum of the three groups is <math>2 \cdot 1 + 1 + 1 + 1 = 5</math> or <math>\boxed{\textbf{(D)}\ 5}</math> | ||
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+ | ~ lovelearning999 | ||
==Video Solutions== | ==Video Solutions== |
Latest revision as of 21:10, 2 October 2024
Contents
Problem
What is the value of
Solution 1
We know that when we subtract negative numbers, .
The equation becomes .
~quacker88
Solution 2
Like Solution 1, we know that when we subtract , that will equal as the opposite/negative of a negative is a positive. Thus, . We can group together a few terms to make our computation a bit simpler. .
~BakedPotato66
Solution 3
Notice has three groups: , ,
The first group, , can be expressed as .
Simplify,
is
The second and third groups can be expressed as .
Simplify,
is
Thus, the sum of the three groups is or
~ lovelearning999
Video Solutions
Video Solution by Education, the study of everything
https://www.youtube.com/watch?v=NpDVTLSi-Ik
~Education, the Study of Everything
Video Solution by TheBeautyofMath
~IceMatrix
Video Solution by WhyMath
~savannahsolver
Video Solution by Alex Explains
https://www.youtube.com/watch?v=GNPAgQ8fSP0&t
~AlexExplains
See Also
2020 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.