Difference between revisions of "1988 AJHSME Problems/Problem 8"
(New page: ==Problem== Betty used a calculator to find the product <math>0.075 \times 2.56</math>. She forgot to enter the decimal points. The calculator showed <math>19200</math>. If Betty had e...) |
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==Problem== | ==Problem== | ||
| − | Betty used a calculator to find the product <math>0.075 \times 2.56</math>. She forgot to enter the decimal points. The calculator showed <math>19200</math>. If Betty had entered the decimal points correctly, the answer would have been | + | Betty used a calculator to find the [[product]] <math>0.075 \times 2.56</math>. She forgot to enter the decimal points. The calculator showed <math>19200</math>. If Betty had entered the decimal points correctly, the answer would have been |
<math>\text{(A)}\ .0192 \qquad \text{(B)}\ .192 \qquad \text{(C)}\ 1.92 \qquad \text{(D)}\ 19.2 \qquad \text{(E)}\ 192</math> | <math>\text{(A)}\ .0192 \qquad \text{(B)}\ .192 \qquad \text{(C)}\ 1.92 \qquad \text{(D)}\ 19.2 \qquad \text{(E)}\ 192</math> | ||
==Solution== | ==Solution== | ||
| − | The decimal point of 0.075 is three away from what Betty punched in, and that of 2.56 is two away. The decimal point is therefore <math>3+2=5</math> | + | The [[decimal point]] of 0.075 is three away from what Betty punched in, and that of 2.56 is two away. The decimal point is therefore <math>3+2=5</math> units to the left of where it should be, so we would want <math>.19200\Rightarrow \mathrm{(B)}</math>. |
==See Also== | ==See Also== | ||
| − | [[ | + | {{AJHSME box|year=1988|num-b=7|num-a=9}} |
| + | [[Category:Introductory Algebra Problems]] | ||
| + | {{MAA Notice}} | ||
Latest revision as of 22:55, 4 July 2013
Problem
Betty used a calculator to find the product 
. She forgot to enter the decimal points. The calculator showed 
. If Betty had entered the decimal points correctly, the answer would have been
Solution
The decimal point of 0.075 is three away from what Betty punched in, and that of 2.56 is two away. The decimal point is therefore 
units to the left of where it should be, so we would want 
.
See Also
| 1988 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 7 |
Followed by Problem 9 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
