Difference between revisions of "1997 AHSME Problems/Problem 4"
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<math> \mathrm{(A)\ } 20\% \qquad \mathrm{(B) \ }25\% \qquad \mathrm{(C) \ } 50\% \qquad \mathrm{(D) \ } 100\% \qquad \mathrm{(E) \ }200\% </math> | <math> \mathrm{(A)\ } 20\% \qquad \mathrm{(B) \ }25\% \qquad \mathrm{(C) \ } 50\% \qquad \mathrm{(D) \ } 100\% \qquad \mathrm{(E) \ }200\% </math> | ||
− | ==Solution 1== | + | __TOC__ |
+ | == Solution == | ||
+ | ===Solution 1=== | ||
Translating each sentence into an equation, <math>a = 1.5c</math> and <math>b = 1.25c</math>. | Translating each sentence into an equation, <math>a = 1.5c</math> and <math>b = 1.25c</math>. | ||
Line 19: | Line 21: | ||
<math>a = 1.2b</math> | <math>a = 1.2b</math> | ||
− | In this case, <math>a</math> is <math>1.2 - 1 = 0.2 = 20\%</math> bigger than <math>b</math>, and the answer is <math>\boxed{ | + | In this case, <math>a</math> is <math>1.2 - 1 = 0.2 = 20\%</math> bigger than <math>b</math>, and the answer is <math>\boxed{A}</math>. |
− | ==Solution 2== | + | ===Solution 2=== |
Arbitrarily assign a value to one of the variables. Since <math>c</math> is the smallest variable, let <math>c = 100</math>. | Arbitrarily assign a value to one of the variables. Since <math>c</math> is the smallest variable, let <math>c = 100</math>. | ||
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If <math>b</math> is <math>25\%</math> larger than <math>c</math>, then <math>b = 125</math>. | If <math>b</math> is <math>25\%</math> larger than <math>c</math>, then <math>b = 125</math>. | ||
− | We see that <math>\frac{a}{b} = \frac{150}{125} = 1.2</math> So, <math>a</math> is <math>20\%</math> bigger than <math>b</math>, and the answer is <math>\boxed{ | + | We see that <math>\frac{a}{b} = \frac{150}{125} = 1.2</math> So, <math>a</math> is <math>20\%</math> bigger than <math>b</math>, and the answer is <math>\boxed{A}</math>. |
− | |||
== See also == | == See also == | ||
{{AHSME box|year=1997|num-b=3|num-a=5}} | {{AHSME box|year=1997|num-b=3|num-a=5}} | ||
+ | |||
+ | [[Category:Introductory Algebra Problems]] | ||
+ | {{MAA Notice}} |
Latest revision as of 14:12, 5 July 2013
Problem
If is
larger than
, and
is
larger than
, then
is what percent larger than
?
Solution
Solution 1
Translating each sentence into an equation, and
.
We want a relationship between and
. Dividing the second equation into the first will cancel the
, so we try that and get:
In this case, is
bigger than
, and the answer is
.
Solution 2
Arbitrarily assign a value to one of the variables. Since is the smallest variable, let
.
If is
larger than
, then
.
If is
larger than
, then
.
We see that So,
is
bigger than
, and the answer is
.
See also
1997 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.