Art of Problem Solving
AoPS Online
Math texts, online classes, and more
for students in grades 5-12.
Visit AoPS Online ‚
Books for Grades 5-12 Online Courses
Beast Academy
Engaging math books and online learning
for students ages 6-13.
Visit Beast Academy ‚
Books for Ages 6-13 Beast Academy Online
AoPS Academy
Small live classes for advanced math
and language arts learners in grades 2-12.
Visit AoPS Academy ‚
Find a Physical Campus Visit the Virtual Campus

Difference between revisions of "2009 AMC 8 Problems/Problem 19"

(Created page with "==Problems== Two angles of an isosceles triangle measure <math> 70^\circ</math> and <math> x^\circ</math>. What is the sum of the three possible values of <math> x</math>? <math...")
 
(→‎Video Solution by OmegaLearn)
 
(9 intermediate revisions by 7 users not shown)
Line 1: Line 1:
−
==Problems==
+
==Problem==
 
Two angles of an isosceles triangle measure <math> 70^\circ</math> and <math> x^\circ</math>. What is the sum of the three possible values of <math> x</math>?
 
Two angles of an isosceles triangle measure <math> 70^\circ</math> and <math> x^\circ</math>. What is the sum of the three possible values of <math> x</math>?
  
Line 7: Line 7:
 
\textbf{(D)}\    165  \qquad
 
\textbf{(D)}\    165  \qquad
 
\textbf{(E)}\    180</math>
 
\textbf{(E)}\    180</math>
 +
 +
 +
==Solution==
 +
 +
There are 3 cases: where <math> x^\circ</math> is a base angle with the <math> 70^\circ</math> as the other angle, where <math> x^\circ</math> is a base angle with <math> 70^\circ</math> as the vertex angle, and where <math> x^\circ</math> is the vertex angle with <math> 70^\circ</math> as a base angle.
 +
 +
Case 1: <math> x^\circ</math> is a base angle with the <math> 70^\circ</math> as the other angle:
 +
Here, <math> x=70</math>, since base angles are congruent.
 +
 +
Case 2: <math> x^\circ</math> is a base angle with <math> 70^\circ</math> as the vertex angle:
 +
Here, the 2 base angles are both <math> x^\circ</math>, so we can use the equation <math> 2x+70=180</math>, which simplifies to <math> x=55</math>.
 +
 +
Case 3: <math> x^\circ</math> is the vertex angle with <math> 70^\circ</math> as a base angle:
 +
Here, both base angles are <math> 70^\circ</math>, since base angles are congruent. Thus, we can use the equation <math> x+140=180</math>, which simplifies to <math> x=40</math>.
 +
 +
Adding up all the cases, we get <math>70+55+40=165</math>, so the answer is <math> \boxed{\textbf{(D)}\    165}</math>.
 +
 +
== Video Solution by OmegaLearn ==
 +
https://youtu.be/FDgcLW4frg8?t=902
 +
 +
~ pi_is_3.14
 +
 +
https://www.youtube.com/watch?v=EO3DphZAlDY  ~David
 +
 +
==Video Solution 2==
 +
https://youtu.be/iB0dcpVREE8 Soo, DRMS, NM
 +
 +
 +
==See Also==
 +
{{AMC8 box|year=2009|num-b=18|num-a=20}}
 +
{{MAA Notice}}

Latest revision as of 18:38, 15 April 2023

Problem

Two angles of an isosceles triangle measure $70^\circ$ and $x^\circ$. What is the sum of the three possible values of $x$?

$\textbf{(A)}\ 95 \qquad \textbf{(B)}\ 125 \qquad \textbf{(C)}\ 140 \qquad \textbf{(D)}\ 165 \qquad \textbf{(E)}\ 180$


Solution

There are 3 cases: where $x^\circ$ is a base angle with the $70^\circ$ as the other angle, where $x^\circ$ is a base angle with $70^\circ$ as the vertex angle, and where $x^\circ$ is the vertex angle with $70^\circ$ as a base angle.

Case 1: $x^\circ$ is a base angle with the $70^\circ$ as the other angle: Here, $x=70$, since base angles are congruent.

Case 2: $x^\circ$ is a base angle with $70^\circ$ as the vertex angle: Here, the 2 base angles are both $x^\circ$, so we can use the equation $2x+70=180$, which simplifies to $x=55$.

Case 3: $x^\circ$ is the vertex angle with $70^\circ$ as a base angle: Here, both base angles are $70^\circ$, since base angles are congruent. Thus, we can use the equation $x+140=180$, which simplifies to $x=40$.

Adding up all the cases, we get $70+55+40=165$, so the answer is $\boxed{\textbf{(D)}\ 165}$.

Video Solution by OmegaLearn

https://youtu.be/FDgcLW4frg8?t=902

~ pi_is_3.14

https://www.youtube.com/watch?v=EO3DphZAlDY ~David

Video Solution 2

https://youtu.be/iB0dcpVREE8 Soo, DRMS, NM


See Also

2009 AMC 8 (Problems • Answer Key • Resources)
Preceded by
Problem 18 		Followed by
Problem 20
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

Retrieved from "https://artofproblemsolving.com/wiki/index.php?title=2009_AMC_8_Problems/Problem_19&oldid=192164"