Difference between revisions of "2010 AMC 10B Problems/Problem 1"
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== Solution == | == Solution == | ||
− | + | <math>100(100-3)-(100\cdot{100}-3)=10000-300-10000+3=-300+3=\boxed{\textbf{(C)}\ -297}</math>. | |
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+ | ==Video Solution== | ||
+ | https://youtu.be/mvMGV8tpqGs | ||
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+ | ~Education, the Study of Everything | ||
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+ | ==Video Solution== | ||
+ | https://youtu.be/uAc9VHtRRPg | ||
+ | |||
+ | ~IceMatrix | ||
==See Also== | ==See Also== | ||
{{AMC10 box|year=2010|ab=B|before=First Problem|num-a=2}} | {{AMC10 box|year=2010|ab=B|before=First Problem|num-a=2}} | ||
+ | {{MAA Notice}} |
Latest revision as of 15:58, 1 August 2022
Problem
What is ?
Solution
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Video Solution
~Education, the Study of Everything
Video Solution
~IceMatrix
See Also
2010 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.