Difference between revisions of "1997 AHSME Problems/Problem 17"
(→Problem) |
m (→Solution: x=k is not horizontal) |
||
(2 intermediate revisions by 2 users not shown) | |||
Line 7: | Line 7: | ||
==Solution== | ==Solution== | ||
− | Since the line <math> | + | Since the line <math>x=k</math> is vertical, we are only concerned with vertical distance. |
In other words, we want to find the value of <math>k</math> for which the distance <math>|\log_5 x - \log_5 (x+4)| = \frac{1}{2}</math> | In other words, we want to find the value of <math>k</math> for which the distance <math>|\log_5 x - \log_5 (x+4)| = \frac{1}{2}</math> | ||
Line 30: | Line 30: | ||
The desired quantity is <math>1 + 5 = 6</math>, and the answer is <math>\boxed{A}</math>. | The desired quantity is <math>1 + 5 = 6</math>, and the answer is <math>\boxed{A}</math>. | ||
− | |||
== See also == | == See also == | ||
{{AHSME box|year=1997|num-b=16|num-a=18}} | {{AHSME box|year=1997|num-b=16|num-a=18}} | ||
+ | {{MAA Notice}} |
Latest revision as of 09:31, 25 September 2016
Problem
A line intersects the graph of and the graph of . The distance between the points of intersection is . Given that , where and are integers, what is ?
Solution
Since the line is vertical, we are only concerned with vertical distance.
In other words, we want to find the value of for which the distance
Since is a strictly increasing function, we have:
The desired quantity is , and the answer is .
See also
1997 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 16 |
Followed by Problem 18 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.