Difference between revisions of "2012 AMC 10B Problems/Problem 1"
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== Problem == | == Problem == | ||
− | Each third-grade classroom at Pearl Creek Elementary has 18 students and 2 pet rabbits. How many more students than rabbits are there in all 4 of the third-grade classrooms? | + | Each third-grade classroom at Pearl Creek Elementary has <math>18</math> students and <math>2</math> pet rabbits. How many more students than rabbits are there in all <math>4</math> of the third-grade classrooms? |
<math> \textbf{(A)}\ 48\qquad\textbf{(B)}\ 56\qquad\textbf{(C)}\ 64\qquad\textbf{(D)}\ 72\qquad\textbf{(E)}\ 80 </math> | <math> \textbf{(A)}\ 48\qquad\textbf{(B)}\ 56\qquad\textbf{(C)}\ 64\qquad\textbf{(D)}\ 72\qquad\textbf{(E)}\ 80 </math> | ||
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== Solution== | == Solution== | ||
In each class, there are <math>18-2=16</math> more students than rabbits. So for all classrooms, the difference between students and rabbits is <math>16 \times 4 = \boxed{\textbf{(C)}\ 64}</math> | In each class, there are <math>18-2=16</math> more students than rabbits. So for all classrooms, the difference between students and rabbits is <math>16 \times 4 = \boxed{\textbf{(C)}\ 64}</math> | ||
+ | |||
+ | ==See Also== | ||
+ | |||
+ | {{AMC10 box|year=2012|ab=B|num-b=1|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 13:32, 16 February 2016
Problem
Each third-grade classroom at Pearl Creek Elementary has students and
pet rabbits. How many more students than rabbits are there in all
of the third-grade classrooms?
Solution
In each class, there are more students than rabbits. So for all classrooms, the difference between students and rabbits is
See Also
2012 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 2 | |
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All AMC 10 Problems and Solutions |
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