Difference between revisions of "1993 AHSME Problems/Problem 9"
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== Solution == | == Solution == | ||
− | <math>\fbox{D}</math> | + | |
+ | Let <math>W</math> be the wealth of the world and <math>P</math> be the population of the world. Hence the wealth of each citizen of <math>A</math> is <math>w_A = \frac{0.01d W}{0.01cP}=\frac{dW}{cP}</math>. Similarly the wealth of each citizen of <math>B</math> is <math>w_B =\frac{eW}{fP}</math>. We divide <math>\frac{w_A}{w_B} = \frac{de}{cf}</math> and see the answer is <math>\fbox{D}</math> | ||
== See also == | == See also == |
Latest revision as of 21:59, 27 May 2021
Problem
Country has
of the world's population and
of the worlds wealth. Country
has
of the world's population and
of its wealth. Assume that the citizens of
share the wealth of
equally,and assume that those of
share the wealth of
equally. Find the ratio of the wealth of a citizen of
to the wealth of a citizen of
.
Solution
Let be the wealth of the world and
be the population of the world. Hence the wealth of each citizen of
is
. Similarly the wealth of each citizen of
is
. We divide
and see the answer is
See also
1993 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 8 |
Followed by Problem 10 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
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