Difference between revisions of "2007 IMO Problems"

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[[2007 IMO Problems/Problem 6 | Solution]]
 
[[2007 IMO Problems/Problem 6 | Solution]]
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{{IMO box|year=2007|before=[[2006 IMO Problems]]|after=[[2008 IMO Problems]]}}

Latest revision as of 08:24, 10 September 2020

Problem 1


Real numbers $a_1, a_2, \dots , a_n$ are given. For each $i$ ($1\le i\le n$) define \[d_i=\max\{a_j:1\le j\le i\}-\min\{a_j:i\le j\le n\}\] and let \[d=\max\{d_i:1\le i\le n\}.\]

(a) Prove that, for any real numbers $x_1\le x_2\le \cdots\le x_n$, \[\max\{|x_i-a_i|:1\le i\le n\}\ge \dfrac{d}{2}   \qquad (*)\]

(b) Show that there are real numbers $x_1\le x_2\le x_n$ such that equality holds in (*)


Solution

Problem 2

Consider five points $A,B,C,D$, and $E$ such that $ABCD$ is a parallelogram and $BCED$ is a cyclic quadrilateral. Let $\ell$ be a line passing through $A$. Suppose that $\ell$ intersects the interior of the segment $DC$ at $F$ and intersects line $BC$ at $G$. Suppose also that $EF=EG=EC$. Prove that $\ell$ is the bisector of $\angle DAB$.

Solution

Problem 3

In a mathematical competition some competitors are friends. Friendship is always mutual. Call a group of competitors a clique if each two of them are friends. (In particular, any group of fewer than two competitors is a clique.) The number of members of a clique is called its size. Given that, in this competition, the largest size of a clique is even, prove that the competitors can be arranged in two rooms such that the largest size of a clique contained in one room is the same as the largest size of a clique contained in the other room.

Solution

Problem 4

In $\triangle ABC$ the bisector of $\angle{BCA}$ intersects the circumcircle again at $R$, the perpendicular bisector of $BC$ at $P$, and the perpendicular bisector of $AC$ at $Q$. The midpoint of $BC$ is $K$ and the midpoint of $AC$ is $L$. Prove that the triangles $RPK$ and $RQL$ have the same area.

Solution

Problem 5

(Kevin Buzzard and Edward Crane, United Kingdom) Let $a$ and $b$ be positive integers. Show that if $4ab-1$ divides $(4a^2-1)^2$, then $a=b$.

Solution

Problem 6

Let $n$ be a positive integer. Consider \[S=\{(x,y,z)~:~x,y,z\in \{0,1,\ldots,n \},~x+y+z>0\}\] as a set of $(n+1)^3-1$ points in three-dimensional space. Determine the smallest possible number of planes, the union of which contain $S$ but does not include $(0,0,0)$.

Solution

2007 IMO (Problems) • Resources
Preceded by
2006 IMO Problems
1 2 3 4 5 6 Followed by
2008 IMO Problems
All IMO Problems and Solutions