Difference between revisions of "2010 UNCO Math Contest II Problems/Problem 2"
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== Solution == | == Solution == | ||
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+ | Notice the rectangle is divided into 10 triangles of equal triangles. Therefore, the shaded area is <math>\frac 25</math> of the area of the rectangle, which is <math>\dfrac 25\cdot 75 \cdot 67 = \boxed {2010}.</math> | ||
== See also == | == See also == |
Latest revision as of 20:51, 13 October 2016
Problem
The rectangle has dimensions .
The diagonal
is divided into five
segments of equal length. Find the
total area of the shaded regions.
Solution
Notice the rectangle is divided into 10 triangles of equal triangles. Therefore, the shaded area is of the area of the rectangle, which is
See also
2010 UNCO Math Contest II (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 | ||
All UNCO Math Contest Problems and Solutions |