Difference between revisions of "1987 AHSME Problems/Problem 5"

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\textbf{(D)}\ 25 \qquad
 
\textbf{(D)}\ 25 \qquad
 
\textbf{(E)}\ 50</math>
 
\textbf{(E)}\ 50</math>
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== Solution ==
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Note that <math>12.5\% = \frac{1}{8}</math>, <math>25\% = \frac{1}{4}</math>, and <math>50\% = \frac{1}{2}</math>. Thus, since the frequencies must be integers, <math>N</math> must be divisible by <math>2</math>, <math>4</math>, and <math>8</math> (so that <math>\frac{N}{8}</math> etc. are integers), or in other words, <math>N</math> is divisible by <math>8</math>. Thus the smallest possible value of <math>N</math> is the smallest positive multiple of <math>8</math>, which is <math>8</math> itself, or <math>\boxed{\text{B}}</math>.
  
 
== See also ==
 
== See also ==
{{AHSME box|year=1987|num-b=3|num-a=5}}   
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{{AHSME box|year=1987|num-b=4|num-a=6}}   
  
 
[[Category: Introductory Algebra Problems]]
 
[[Category: Introductory Algebra Problems]]
 
{{MAA Notice}}
 
{{MAA Notice}}

Latest revision as of 11:25, 1 March 2018

Problem

A student recorded the exact percentage frequency distribution for a set of measurements, as shown below. However, the student neglected to indicate $N$, the total number of measurements. What is the smallest possible value of $N$?

\[\begin{tabular}{c c}\text{measured value}&\text{percent frequency}\\ \hline 0 & 12.5\\ 1 & 0\\ 2 & 50\\ 3 & 25\\ 4 & 12.5\\ \hline\ & 100\\ \end{tabular}\]

$\textbf{(A)}\ 5 \qquad \textbf{(B)}\ 8 \qquad \textbf{(C)}\ 16 \qquad \textbf{(D)}\ 25 \qquad \textbf{(E)}\ 50$

Solution

Note that $12.5\% = \frac{1}{8}$, $25\% = \frac{1}{4}$, and $50\% = \frac{1}{2}$. Thus, since the frequencies must be integers, $N$ must be divisible by $2$, $4$, and $8$ (so that $\frac{N}{8}$ etc. are integers), or in other words, $N$ is divisible by $8$. Thus the smallest possible value of $N$ is the smallest positive multiple of $8$, which is $8$ itself, or $\boxed{\text{B}}$.

See also

1987 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
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