Difference between revisions of "2019 AMC 12A Problems/Problem 2"

Revision as of 01:29, 10 February 2019

Suppose $a$ is $150\%$ of $b$ . What percent of $a$ is $3b$ ?

$\textbf{(A) } 50 \qquad \textbf{(B) } 66\frac{2}{3} \qquad \textbf{(C) } 150 \qquad \textbf{(D) } 200 \qquad \textbf{(E) } 450$

Since $a=1.5b$ , that means $b=a/1.5$ . We multiply by 3 to get a $3b$ term, to yield $3b=2a$ .

$2a$ is $\boxed{200\%}$ of $a$ .

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2019 AMC 12A (Problems • Answer Key • Resources)
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All AMC 12 Problems and Solutions

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 <math>2a</math> is <math>\boxed{200\%}</math> of <math>a</math>.
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 ==See Also==