Difference between revisions of "1957 AHSME Problems/Problem 8"
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| − | = | + | The numbers <math>x,\,y,\,z</math> are proportional to <math>2,\,3,\,5</math>. The sum of <math>x, y</math>, and <math>z</math> is <math>100</math>. The number y is given by the equation <math>y = ax - 10</math>. Then a is: |
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| + | <math>\textbf{(A)}\ 2 \qquad \textbf{(B)}\ \frac{3}{2}\qquad \textbf{(C)}\ 3\qquad \textbf{(D)}\ \frac{5}{2}\qquad \textbf{(E)}\ 4 </math> | ||
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==Solution== | ==Solution== | ||
==See Also== | ==See Also== | ||
{{AHSME box|year=1957|num-b=7|num-a=9}} | {{AHSME box|year=1957|num-b=7|num-a=9}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 11:23, 12 October 2020
The numbers 
are proportional to 
. The sum of 
, and 
is 
. The number y is given by the equation 
. Then a is:
Solution
See Also
| 1957 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 7 |
Followed by Problem 9 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
