Difference between revisions of "1997 AIME Problems/Problem 14"
Ninja glace (talk | contribs) (→Solution) |
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z^{1997}&=&e^{2\pi ik}\\ | z^{1997}&=&e^{2\pi ik}\\ | ||
z&=&e^{\frac{2\pi ik}{1997}} | z&=&e^{\frac{2\pi ik}{1997}} | ||
− | \end{eqnarray*}<math> | + | \end{eqnarray*}<\math> |
== See also == | == See also == | ||
* [[1997 AIME Problems]]</math> | * [[1997 AIME Problems]]</math> |
Revision as of 20:10, 7 March 2007
Problem
Let and
be distinct, randomly chosen roots of the equation
. Let
be the probability that
, where
and
are relatively prime positive integers. Find
.
Solution
The solution requires the use of Euler's formula:
If , where k is any constant, the equation reduces to:
$\begin{eqnarray*}
e^{2\pi ik}&=&\cos(2\pi k)+i\sin(2\pi k)\\
&=&1+0i\\
&=&1+0\\
&=&1\\
z^{1997}-1&=&0\\
z^{1997}&=&1\\
z^{1997}&=&e^{2\pi ik}\\
z&=&e^{\frac{2\pi ik}{1997}}
\end{eqnarray*}<\math>
== See also ==
- [[1997 AIME Problems]]$ (Error compiling LaTeX. Unknown error_msg)