Difference between revisions of "2021 AMC 10A Problems/Problem 3"

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==Solution==
 
==Solution==
<math> \textbf{(A)}\ 12pi + 14\qquad\textbf </math>
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<math> \textbf{(A)}\ 12pi + 14\qquad\textbf{(B)}\ 11pi\qquad\textbf{(C)}\ 10\qquad\textbf{(D)}\ 32pi\qquad\textbf{(E)}\ 22pi </math>
  
 
==Note==
 
==Note==

Revision as of 21:19, 31 January 2021

Problem

If a circle is inscribed in a square and then have right triangles with legs on the sides of the square and within the area between the circle and the square, what is the area inside the square but outside the triangles and the circle if the area of the circle is equal to the perimeter of the square?

$\textbf{(A)}\ 12pi + 14\qquad\textbf{(B)}\ 11pi\qquad\textbf{(C)}\ 10\qquad\textbf{(D)}\ 32pi\qquad\textbf{(E)}\ 22pi$

Solution

$\textbf{(A)}\ 12pi + 14\qquad\textbf{(B)}\ 11pi\qquad\textbf{(C)}\ 10\qquad\textbf{(D)}\ 32pi\qquad\textbf{(E)}\ 22pi$

Note

This problem might also be on the AMC 12A. If so, please redirect it there.

See also

2021 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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