Difference between revisions of "2021 AMC 10A Problems/Problem 1"
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<math>\textbf{(A) } 1 \qquad\textbf{(B) } 2 \qquad\textbf{(C) } 5 \qquad\textbf{(D) } 8 \qquad\textbf{(E) } 12</math> | <math>\textbf{(A) } 1 \qquad\textbf{(B) } 2 \qquad\textbf{(C) } 5 \qquad\textbf{(D) } 8 \qquad\textbf{(E) } 12</math> | ||
| − | == Solution == | + | == Solution 1== |
<math>(4-2)-(9-3)+(16-4)=2-6+12=8.</math> This corresponds to <math>\boxed{\textbf{(D) } 8}</math> | <math>(4-2)-(9-3)+(16-4)=2-6+12=8.</math> This corresponds to <math>\boxed{\textbf{(D) } 8}</math> | ||
Revision as of 17:18, 17 February 2021
Contents
Problem
What is the value of ![\[(2^2-2)-(3^2-3)+(4^2-4)\]](http://latex.artofproblemsolving.com/f/b/f/fbf9a3889b146c23eb653b9dc16255c03a229dfe.png)
Solution 1
This corresponds to 
-happykeeper
Solution 2
~MRENTHUSIASM
Video Solution #0(Very Very Quick Computation)
https://www.youtube.com/watch?v=m0_UMI2mnZs&list=PLexHyfQ8DMuKqltG3cHT7Di4jhVl6L4YJ&index=2 ~North America Mathematic Contest Go Go Go
Video Solution #1(Quick Computation)
https://youtu.be/C3n2hgBhyXc?t=37 ~ThePuzzlr
Video Solution (Arithmetic Computation)
~ pi_is_3.14
Video Solution (Simple)
~ Education, the Study of everything
Video Solution 5
~savannahsolver
See Also
| 2021 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
