Difference between revisions of "2016 AMC 8 Problems/Problem 12"
Hashtagmath (talk | contribs) |
Hashtagmath (talk | contribs) (→Problem 12) |
||
| Line 1: | Line 1: | ||
| − | ==Problem | + | ==Problem == |
Jefferson Middle School has the same number of boys and girls. <math>\frac{3}{4}</math> of the girls and <math>\frac{2}{3}</math> | Jefferson Middle School has the same number of boys and girls. <math>\frac{3}{4}</math> of the girls and <math>\frac{2}{3}</math> | ||
Revision as of 16:16, 21 April 2021
Contents
Problem
Jefferson Middle School has the same number of boys and girls. 
of the girls and 
of the boys went on a field trip. What fraction of the students on the field trip were girls?
Solution 1
Set the number of children to a number that is divisible by two, four, and three. In this question, the number of children in the school is not a specific number because there are no actual numbers in the question, only ratios.This way, we can calculate the answer without dealing with decimals.
is a number that works. There will be 
girls and boys. So, there will be
= 
girls on the trip and 
= 
boys on the trip.
The total number of children on the trip is 
, so the fraction of girls on the trip is 
or 
Solution 2
Let there be 
boys and 
girls in the school. We see 
, which means 
kids went on the trip and 
kids are girls. So, the answer is 
, which is
See Also
| 2016 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 11 |
Followed by Problem 13 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
