Difference between revisions of "2023 AMC 8 Problems/Problem 24"

(Problem)
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<cmath>\textbf{(A) } 14.6 \qquad \textbf{(B) } 14.8 \qquad \textbf{(C) } 15 \qquad \textbf{(D) } 15.2 \qquad \textbf{(E) } ~15.4</cmath>
 
<cmath>\textbf{(A) } 14.6 \qquad \textbf{(B) } 14.8 \qquad \textbf{(C) } 15 \qquad \textbf{(D) } 15.2 \qquad \textbf{(E) } ~15.4</cmath>
\end{exx}
 
  
 
==Video Solution==
 
==Video Solution==
  
 
https://youtu.be/almtw4n-92A
 
https://youtu.be/almtw4n-92A

Revision as of 18:22, 24 January 2023

Problem

Isosceles $\triangle ABC$ has equal side lengths $AB$ and $BC$. In the figure below, segments are drawn parallel to $\overline{AC}$ so that the shaded portions of $\triangle ABC$ have the same area. The heights of the two unshaded portions are 11 and 5 units, respectively. What is the height of $h$ of $\triangle ABC$?

  • Add asymptote diagram*

\[\textbf{(A) } 14.6 \qquad \textbf{(B) } 14.8 \qquad \textbf{(C) } 15 \qquad \textbf{(D) } 15.2 \qquad \textbf{(E) } ~15.4\]

Video Solution

https://youtu.be/almtw4n-92A