Difference between revisions of "2005 IMO Problems/Problem 5"

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points <math>E</math> and <math>F</math> lie of the sides <math>BC</math> and <math>DA</math>, respectively, and satisfy <math>BE = DF</math>. The lines <math>AC</math> and <math>BD</math> meet at <math>P</math>, the lines <math>BD</math> and <math>EF</math> meet at <math>Q</math>, the lines <math>EF</math> and <math>AC</math> meet at <math>R</math>. Prove that the circumcircles of the triangles <math>PQR</math>, as <math>E</math> and <math>F</math> vary, have a common point other than <math>P</math>.
 
points <math>E</math> and <math>F</math> lie of the sides <math>BC</math> and <math>DA</math>, respectively, and satisfy <math>BE = DF</math>. The lines <math>AC</math> and <math>BD</math> meet at <math>P</math>, the lines <math>BD</math> and <math>EF</math> meet at <math>Q</math>, the lines <math>EF</math> and <math>AC</math> meet at <math>R</math>. Prove that the circumcircles of the triangles <math>PQR</math>, as <math>E</math> and <math>F</math> vary, have a common point other than <math>P</math>.
  
==Solution==
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==Solution (Video Solution) ==
{{solution}}
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https://youtu.be/Ceap-NC2nW8
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==See Also==
 
==See Also==
  
 
{{IMO box|year=2005|num-b=4|num-a=6}}
 
{{IMO box|year=2005|num-b=4|num-a=6}}

Revision as of 08:21, 4 September 2024

Problem

Let $ABCD$ be a fixed convex quadrilateral with $BC = DA$ and $BC \nparallel DA$. Let two variable points $E$ and $F$ lie of the sides $BC$ and $DA$, respectively, and satisfy $BE = DF$. The lines $AC$ and $BD$ meet at $P$, the lines $BD$ and $EF$ meet at $Q$, the lines $EF$ and $AC$ meet at $R$. Prove that the circumcircles of the triangles $PQR$, as $E$ and $F$ vary, have a common point other than $P$.

Solution (Video Solution)

https://youtu.be/Ceap-NC2nW8


See Also

2005 IMO (Problems) • Resources
Preceded by
Problem 4
1 2 3 4 5 6 Followed by
Problem 6
All IMO Problems and Solutions