Difference between revisions of "2007 AMC 10A Problems/Problem 3"

Revision as of 14:34, 6 January 2008

Problem

An aquarium has a rectangular base that measures $100$ cm by $40$ cm and has a height of $50$ cm. It is filled with water to a height of $40$ cm. A brick with a rectangular base that measures $40$ cm by $20$ cm and a height of $10$ cm is placed in the aquarium. By how many centimeters does the water rise?

$\text{(A)}\ 0.5 \qquad \text{(B)}\ 1 \qquad \text{(C)}\ 1.5 \qquad \text{(D)}\ 2 \qquad \text{(E)}\ 2.5$

Solution

The volume of the brick is $40 \times 20 \times 10 = 8000$ . Thus the water volume rose $8000 = 100 \times 40 \times h \Longrightarrow h = 2\ \mathrm{(D)}$ .

2007 AMC 10A (Problems • Answer Key • Resources)
Preceded by Problem 2	Followed by Problem 4
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AMC 10 Problems and Solutions

@@ Line 8: / Line 8: @@
 == See also ==
-{{AMC10 box|year=2007|ab=A|num-b=8|num-a=10}}
+{{AMC10 box|year=2007|ab=A|num-b=2|num-a=4}}
 [[Category:Introductory Algebra Problems]]

Page

Toolbox

Search

Difference between revisions of "2007 AMC 10A Problems/Problem 3"

Revision as of 14:34, 6 January 2008

Problem

Solution

See also