Difference between revisions of "2002 AMC 10P Problems/Problem 2"

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#REDIRECT [[2002 AMC 12P Problems/Problem 2]]
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== Problem 2 ==
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The sum of eleven consecutive integers is <math>2002.</math> What is the smallest of these integers?
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<math>
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\text{(A) }175
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\qquad
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\text{(B) }177
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\qquad
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\text{(C) }179
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\qquad
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\text{(D) }180
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\qquad
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\text{(E) }181
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</math>
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== Solution 1 ==
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== See Also ==

Revision as of 07:48, 15 July 2024

Problem 2

The sum of eleven consecutive integers is $2002.$ What is the smallest of these integers?

$\text{(A) }175 \qquad \text{(B) }177 \qquad \text{(C) }179 \qquad \text{(D) }180 \qquad \text{(E) }181$

Solution 1

See Also