Difference between revisions of "2019 AMC 10A Problems/Problem 1"

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== Solution ==  
 
== Solution ==  
<math>2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9</math>
+
<math>2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9=  1+1 = \boxed{\textbf{(C) } 2}</math>.
 
 
<math>=  1+1 = \boxed{\textbf{(C) } 2}</math>.
 
  
 
==Video Solution by Education, the Study of Everything==
 
==Video Solution by Education, the Study of Everything==

Revision as of 11:54, 16 July 2024

Problem

What is the value of \[2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9?\]

$\textbf{(A) } 0 \qquad\textbf{(B) } 1 \qquad\textbf{(C) } 2 \qquad\textbf{(D) } 3 \qquad\textbf{(E) } 4$

Solution

$2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9=  1+1 = \boxed{\textbf{(C) } 2}$.

Video Solution by Education, the Study of Everything

https://youtu.be/K8je0WYBHFc

~Education, The Study Of Everything

Video Solution by WhyMath

https://youtu.be/Ad8WKcwZcTA

~savannahsolver

Video Solution by T2L Academy

https://www.youtube.com/watch?v=OhCy9c2RTFo&list=PLbhMrFqoXXwnSCZShTPinX9ZHWjzIlQr_&index=1

See Also

2019 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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